j^2-12j+23=0

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Solution for j^2-12j+23=0 equation:


Simplifying
j2 + -12j + 23 = 0

Reorder the terms:
23 + -12j + j2 = 0

Solving
23 + -12j + j2 = 0

Solving for variable 'j'.

Begin completing the square.

Move the constant term to the right:

Add '-23' to each side of the equation.
23 + -12j + -23 + j2 = 0 + -23

Reorder the terms:
23 + -23 + -12j + j2 = 0 + -23

Combine like terms: 23 + -23 = 0
0 + -12j + j2 = 0 + -23
-12j + j2 = 0 + -23

Combine like terms: 0 + -23 = -23
-12j + j2 = -23

The j term is -12j.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12j + 36 + j2 = -23 + 36

Reorder the terms:
36 + -12j + j2 = -23 + 36

Combine like terms: -23 + 36 = 13
36 + -12j + j2 = 13

Factor a perfect square on the left side:
(j + -6)(j + -6) = 13

Calculate the square root of the right side: 3.605551275

Break this problem into two subproblems by setting 
(j + -6) equal to 3.605551275 and -3.605551275.

Subproblem 1

j + -6 = 3.605551275 Simplifying j + -6 = 3.605551275 Reorder the terms: -6 + j = 3.605551275 Solving -6 + j = 3.605551275 Solving for variable 'j'. Move all terms containing j to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + j = 3.605551275 + 6 Combine like terms: -6 + 6 = 0 0 + j = 3.605551275 + 6 j = 3.605551275 + 6 Combine like terms: 3.605551275 + 6 = 9.605551275 j = 9.605551275 Simplifying j = 9.605551275

Subproblem 2

j + -6 = -3.605551275 Simplifying j + -6 = -3.605551275 Reorder the terms: -6 + j = -3.605551275 Solving -6 + j = -3.605551275 Solving for variable 'j'. Move all terms containing j to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + j = -3.605551275 + 6 Combine like terms: -6 + 6 = 0 0 + j = -3.605551275 + 6 j = -3.605551275 + 6 Combine like terms: -3.605551275 + 6 = 2.394448725 j = 2.394448725 Simplifying j = 2.394448725

Solution

The solution to the problem is based on the solutions from the subproblems. j = {9.605551275, 2.394448725}

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